x2+3(x-1)=x2+5

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Solution for x2+3(x-1)=x2+5 equation: 



x2+3(x-1)=x2+5

We move all terms to the left:

x2+3(x-1)-(x2+5)=0

We add all the numbers together, and all the variables

-(+x^2+5)+x2+3(x-1)=0

We add all the numbers together, and all the variables

x^2-(+x^2+5)+3(x-1)=0

We multiply parentheses

x^2-(+x^2+5)+3x-3=0

We get rid of parentheses

x^2-x^2+3x-5-3=0

We add all the numbers together, and all the variables

3x-8=0

We move all terms containing x to the left, all other terms to the right

3x=8

x=8/3

x=2+2/3

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