x2+300x=15000

Solution for x2+300x=15000 equation:

x2+300x=15000

We move all terms to the left:

x2+300x-(15000)=0

We add all the numbers together, and all the variables

x^2+300x-15000=0

a = 1; b = 300; c = -15000;
Δ = b2-4ac
Δ = 3002-4·1·(-15000)
Δ = 150000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{150000}=\sqrt{10000*15}=\sqrt{10000}*\sqrt{15}=100\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-100\sqrt{15}}{2*1}=\frac{-300-100\sqrt{15}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+100\sqrt{15}}{2*1}=\frac{-300+100\sqrt{15}}{2}
$