x2+30x+161=0

Solution for x2+30x+161=0 equation:

x2+30x+161=0

We add all the numbers together, and all the variables

x^2+30x+161=0

a = 1; b = 30; c = +161;
Δ = b2-4ac
Δ = 302-4·1·161
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-16}{2*1}=\frac{-46}{2}
=-23
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+16}{2*1}=\frac{-14}{2}
=-7
$