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x2+32x+207=0
We add all the numbers together, and all the variables
x^2+32x+207=0
a = 1; b = 32; c = +207;
Δ = b2-4ac
Δ = 322-4·1·207
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-14}{2*1}=\frac{-46}{2} =-23 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+14}{2*1}=\frac{-18}{2} =-9 $
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