x2+32x-68=0

Solution for x2+32x-68=0 equation:

X2+32X-68=0

We add all the numbers together, and all the variables

X^2+32X-68=0

a = 1; b = 32; c = -68;
Δ = b2-4ac
Δ = 322-4·1·(-68)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-36}{2*1}=\frac{-68}{2}
=-34
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+36}{2*1}=\frac{4}{2}
=2
$