x2+33x+260=0

Solution for x2+33x+260=0 equation:

x2+33x+260=0

We add all the numbers together, and all the variables

x^2+33x+260=0

a = 1; b = 33; c = +260;
Δ = b2-4ac
Δ = 332-4·1·260
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-7}{2*1}=\frac{-40}{2}
=-20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+7}{2*1}=\frac{-26}{2}
=-13
$