x2+34x=1700x=1x

Solution for x2+34x=1700x=1x equation:

x2+34x=1700x=1x

We move all terms to the left:

x2+34x-(1700x)=0

We add all the numbers together, and all the variables

x^2-1666x=0

a = 1; b = -1666; c = 0;
Δ = b2-4ac
Δ = -16662-4·1·0
Δ = 2775556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2775556}=1666$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1666)-1666}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1666)+1666}{2*1}=\frac{3332}{2}
=1666
$