x2+35x=105

Solution for x2+35x=105 equation:

x2+35x=105

We move all terms to the left:

x2+35x-(105)=0

We add all the numbers together, and all the variables

x^2+35x-105=0

a = 1; b = 35; c = -105;
Δ = b2-4ac
Δ = 352-4·1·(-105)
Δ = 1645
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{1645}}{2*1}=\frac{-35-\sqrt{1645}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{1645}}{2*1}=\frac{-35+\sqrt{1645}}{2}
$