x2+36x+180=0

Solution for x2+36x+180=0 equation:

x2+36x+180=0

We add all the numbers together, and all the variables

x^2+36x+180=0

a = 1; b = 36; c = +180;
Δ = b2-4ac
Δ = 362-4·1·180
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-24}{2*1}=\frac{-60}{2}
=-30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+24}{2*1}=\frac{-12}{2}
=-6
$