x2+39x-1000=0

Solution for x2+39x-1000=0 equation:

x2+39x-1000=0

We add all the numbers together, and all the variables

x^2+39x-1000=0

a = 1; b = 39; c = -1000;
Δ = b2-4ac
Δ = 392-4·1·(-1000)
Δ = 5521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-\sqrt{5521}}{2*1}=\frac{-39-\sqrt{5521}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+\sqrt{5521}}{2*1}=\frac{-39+\sqrt{5521}}{2}
$