x2+3=(x+1)2

Solution for x2+3=(x+1)2 equation:

x2+3=(x+1)2

We move all terms to the left:

x2+3-((x+1)2)=0

We add all the numbers together, and all the variables

x^2-((x+1)2)+3=0


We calculate terms in parentheses: -((x+1)2), so:

(x+1)2

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)


We get rid of parentheses

x^2-2x-2+3=0

We add all the numbers together, and all the variables

x^2-2x+1=0

a = 1; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{2}{2}=1$