x2+3x+2=(x+2)x

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Solution for x2+3x+2=(x+2)x equation: 



x2+3x+2=(x+2)x

We move all terms to the left:

x2+3x+2-((x+2)x)=0

We add all the numbers together, and all the variables

x^2+3x-((x+2)x)+2=0



We calculate terms in parentheses: -((x+2)x), so:

(x+2)x

We multiply parentheses

x^2+2x

Back to the equation:

-(x^2+2x)



We get rid of parentheses

x^2-x^2+3x-2x+2=0

We add all the numbers together, and all the variables

x+2=0

We move all terms containing x to the left, all other terms to the right

x=-2

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