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x2+3x-11=-3x^2-4x+19
We move all terms to the left:
x2+3x-11-(-3x^2-4x+19)=0
We add all the numbers together, and all the variables
x^2-(-3x^2-4x+19)+3x-11=0
We get rid of parentheses
x^2+3x^2+4x+3x-19-11=0
We add all the numbers together, and all the variables
4x^2+7x-30=0
a = 4; b = 7; c = -30;
Δ = b2-4ac
Δ = 72-4·4·(-30)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-23}{2*4}=\frac{-30}{8} =-3+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+23}{2*4}=\frac{16}{8} =2 $
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