x2+3x-4=x2+x+1

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Solution for x2+3x-4=x2+x+1 equation: 



x2+3x-4=x2+x+1

We move all terms to the left:

x2+3x-4-(x2+x+1)=0

We add all the numbers together, and all the variables

-(+x^2+x+1)+x2+3x-4=0

We add all the numbers together, and all the variables

x^2-(+x^2+x+1)+3x-4=0

We get rid of parentheses

x^2-x^2-x+3x-1-4=0

We add all the numbers together, and all the variables

2x-5=0

We move all terms containing x to the left, all other terms to the right

2x=5

x=5/2

x=2+1/2

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