x2+3x-650=0

Solution for x2+3x-650=0 equation:

x2+3x-650=0

We add all the numbers together, and all the variables

x^2+3x-650=0

a = 1; b = 3; c = -650;
Δ = b2-4ac
Δ = 32-4·1·(-650)
Δ = 2609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{2609}}{2*1}=\frac{-3-\sqrt{2609}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{2609}}{2*1}=\frac{-3+\sqrt{2609}}{2}
$