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x2+3x=1/7
We move all terms to the left:
x2+3x-(1/7)=0
We add all the numbers together, and all the variables
x2+3x-(+1/7)=0
We add all the numbers together, and all the variables
x^2+3x-(+1/7)=0
We get rid of parentheses
x^2+3x-1/7=0
We multiply all the terms by the denominator
x^2*7+3x*7-1=0
Wy multiply elements
7x^2+21x-1=0
a = 7; b = 21; c = -1;
Δ = b2-4ac
Δ = 212-4·7·(-1)
Δ = 469
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{469}}{2*7}=\frac{-21-\sqrt{469}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{469}}{2*7}=\frac{-21+\sqrt{469}}{14} $
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