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x2+4.5x-20.25=0
We add all the numbers together, and all the variables
x^2+4.5x-20.25=0
a = 1; b = 4.5; c = -20.25;
Δ = b2-4ac
Δ = 4.52-4·1·(-20.25)
Δ = 101.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.5)-\sqrt{101.25}}{2*1}=\frac{-4.5-\sqrt{101.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.5)+\sqrt{101.25}}{2*1}=\frac{-4.5+\sqrt{101.25}}{2} $
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