x2+400x-60000=0

Solution for x2+400x-60000=0 equation:

x2+400x-60000=0

We add all the numbers together, and all the variables

x^2+400x-60000=0

a = 1; b = 400; c = -60000;
Δ = b2-4ac
Δ = 4002-4·1·(-60000)
Δ = 400000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{400000}=\sqrt{40000*10}=\sqrt{40000}*\sqrt{10}=200\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(400)-200\sqrt{10}}{2*1}=\frac{-400-200\sqrt{10}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(400)+200\sqrt{10}}{2*1}=\frac{-400+200\sqrt{10}}{2}
$