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x2+401x-6240=0
We add all the numbers together, and all the variables
x^2+401x-6240=0
a = 1; b = 401; c = -6240;
Δ = b2-4ac
Δ = 4012-4·1·(-6240)
Δ = 185761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{185761}=431$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(401)-431}{2*1}=\frac{-832}{2} =-416 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(401)+431}{2*1}=\frac{30}{2} =15 $
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