x2+47x-150=0

Solution for x2+47x-150=0 equation:

x2+47x-150=0

We add all the numbers together, and all the variables

x^2+47x-150=0

a = 1; b = 47; c = -150;
Δ = b2-4ac
Δ = 472-4·1·(-150)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2809}=53$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-53}{2*1}=\frac{-100}{2}
=-50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+53}{2*1}=\frac{6}{2}
=3
$