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x2+48x-756=0
We add all the numbers together, and all the variables
x^2+48x-756=0
a = 1; b = 48; c = -756;
Δ = b2-4ac
Δ = 482-4·1·(-756)
Δ = 5328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5328}=\sqrt{144*37}=\sqrt{144}*\sqrt{37}=12\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-12\sqrt{37}}{2*1}=\frac{-48-12\sqrt{37}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+12\sqrt{37}}{2*1}=\frac{-48+12\sqrt{37}}{2} $
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