x2+4x+10=3

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Solution for x2+4x+10=3 equation: 



x2+4x+10=3

We move all terms to the left:

x2+4x+10-(3)=0

We add all the numbers together, and all the variables

x^2+4x+7=0

a = 1; b = 4; c = +7;
Δ = b2-4ac
Δ = 42-4·1·7
Δ = -12
Delta is less than zero, so there is no solution for the equation

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