x2+4x+4=0x2+20=0

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Solution for x2+4x+4=0x2+20=0 equation:



x2+4x+4=0x^2+20=0
We move all terms to the left:
x2+4x+4-(0x^2+20)=0
We add all the numbers together, and all the variables
x^2+4x-(0x^2+20)+4=0
We get rid of parentheses
x^2-0x^2+4x-20+4=0
We add all the numbers together, and all the variables
4x-16=0
We move all terms containing x to the left, all other terms to the right
4x=16
x=16/4
x=4

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