If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x2+4x+4=3x+6
We move all terms to the left:
x2+4x+4-(3x+6)=0
We add all the numbers together, and all the variables
x^2+4x-(3x+6)+4=0
We get rid of parentheses
x^2+4x-3x-6+4=0
We add all the numbers together, and all the variables
x^2+x-2=0
a = 1; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·1·(-2)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-3}{2*1}=\frac{-4}{2} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+3}{2*1}=\frac{2}{2} =1 $
| 4g=-242 | | 8(z+2)=4(z+1)-12 | | 9-n=-4n | | 7-7z=-9-9-2z | | 76/4=x | | f+3=-5 | | -9m=-10m+9 | | 3x-(x+8)=-10 | | 10-s=-6+3s | | 300-72=3x | | -z=z-10 | | 0.02(5-x)0.03=0.5(7x+x) | | -9-10u=-5-9u | | 8-9d=-10d | | 3x+7=10-7 | | 2(x+1)=-7x+11 | | 2x+11=x-4 | | 6-2q=-q | | 2x+3(+-10)=45 | | 11x-8=2x+10 | | 144-u=248 | | r=-10+r | | (-3)/n=(6)/n-1 | | y²-8=2y | | 11x=+2+3+8 | | 0.4*(x-3)-4=0.8+x | | 8u-3u-u=16 | | -0.5x+5=10 | | 18x+10=12x+13 | | 114=m-98 | | 10x+1x=+4+6 | | (4+y)^2-(4+y)-20=0 |