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x2+4x-1085=0
We add all the numbers together, and all the variables
x^2+4x-1085=0
a = 1; b = 4; c = -1085;
Δ = b2-4ac
Δ = 42-4·1·(-1085)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-66}{2*1}=\frac{-70}{2} =-35 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+66}{2*1}=\frac{62}{2} =31 $
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