x2+4x-1596=0

Solution for x2+4x-1596=0 equation:

x2+4x-1596=0

We add all the numbers together, and all the variables

x^2+4x-1596=0

a = 1; b = 4; c = -1596;
Δ = b2-4ac
Δ = 42-4·1·(-1596)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-80}{2*1}=\frac{-84}{2}
=-42
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+80}{2*1}=\frac{76}{2}
=38
$