x2+4x-1=(x-1)(x-2)

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Solution for x2+4x-1=(x-1)(x-2) equation: 



x2+4x-1=(x-1)(x-2)

We move all terms to the left:

x2+4x-1-((x-1)(x-2))=0

We add all the numbers together, and all the variables

x^2+4x-((x-1)(x-2))-1=0

We multiply parentheses ..

x^2-((+x^2-2x-1x+2))+4x-1=0



We calculate terms in parentheses: -((+x^2-2x-1x+2)), so:

(+x^2-2x-1x+2)

We get rid of parentheses

x^2-2x-1x+2

We add all the numbers together, and all the variables

x^2-3x+2

Back to the equation:

-(x^2-3x+2)



We add all the numbers together, and all the variables

x^2+4x-(x^2-3x+2)-1=0

We get rid of parentheses

x^2-x^2+4x+3x-2-1=0

We add all the numbers together, and all the variables

7x-3=0

We move all terms containing x to the left, all other terms to the right

7x=3

x=3/7

x=3/7

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