x2+50x+624=0

Solution for x2+50x+624=0 equation:

x2+50x+624=0

We add all the numbers together, and all the variables

x^2+50x+624=0

a = 1; b = 50; c = +624;
Δ = b2-4ac
Δ = 502-4·1·624
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2}{2*1}=\frac{-52}{2}
=-26
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2}{2*1}=\frac{-48}{2}
=-24
$