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x2+51x-594=0
We add all the numbers together, and all the variables
x^2+51x-594=0
a = 1; b = 51; c = -594;
Δ = b2-4ac
Δ = 512-4·1·(-594)
Δ = 4977
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4977}=\sqrt{9*553}=\sqrt{9}*\sqrt{553}=3\sqrt{553}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-3\sqrt{553}}{2*1}=\frac{-51-3\sqrt{553}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+3\sqrt{553}}{2*1}=\frac{-51+3\sqrt{553}}{2} $
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