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x2+52x=3
We move all terms to the left:
x2+52x-(3)=0
We add all the numbers together, and all the variables
x^2+52x-3=0
a = 1; b = 52; c = -3;
Δ = b2-4ac
Δ = 522-4·1·(-3)
Δ = 2716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2716}=\sqrt{4*679}=\sqrt{4}*\sqrt{679}=2\sqrt{679}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-2\sqrt{679}}{2*1}=\frac{-52-2\sqrt{679}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+2\sqrt{679}}{2*1}=\frac{-52+2\sqrt{679}}{2} $
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