x2+5x+4=(x+1)(x+4)

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Solution for x2+5x+4=(x+1)(x+4) equation: 



x2+5x+4=(x+1)(x+4)

We move all terms to the left:

x2+5x+4-((x+1)(x+4))=0

We add all the numbers together, and all the variables

x^2+5x-((x+1)(x+4))+4=0

We multiply parentheses ..

x^2-((+x^2+4x+x+4))+5x+4=0



We calculate terms in parentheses: -((+x^2+4x+x+4)), so:

(+x^2+4x+x+4)

We get rid of parentheses

x^2+4x+x+4

We add all the numbers together, and all the variables

x^2+5x+4

Back to the equation:

-(x^2+5x+4)



We add all the numbers together, and all the variables

x^2+5x-(x^2+5x+4)+4=0

We get rid of parentheses

x^2-x^2+5x-5x-4+4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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