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x2+5x-126=0
We add all the numbers together, and all the variables
x^2+5x-126=0
a = 1; b = 5; c = -126;
Δ = b2-4ac
Δ = 52-4·1·(-126)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-23}{2*1}=\frac{-28}{2} =-14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+23}{2*1}=\frac{18}{2} =9 $
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