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x2+5x-15=x-3
We move all terms to the left:
x2+5x-15-(x-3)=0
We add all the numbers together, and all the variables
x^2+5x-(x-3)-15=0
We get rid of parentheses
x^2+5x-x+3-15=0
We add all the numbers together, and all the variables
x^2+4x-12=0
a = 1; b = 4; c = -12;
Δ = b2-4ac
Δ = 42-4·1·(-12)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8}{2*1}=\frac{-12}{2} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8}{2*1}=\frac{4}{2} =2 $
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