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x2+5x-9.75=0
We add all the numbers together, and all the variables
x^2+5x-9.75=0
a = 1; b = 5; c = -9.75;
Δ = b2-4ac
Δ = 52-4·1·(-9.75)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-8}{2*1}=\frac{-13}{2} =-6+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+8}{2*1}=\frac{3}{2} =1+1/2 $
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