x2+60x-7200=0

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Solution for x2+60x-7200=0 equation:



x2+60x-7200=0
We add all the numbers together, and all the variables
x^2+60x-7200=0
a = 1; b = 60; c = -7200;
Δ = b2-4ac
Δ = 602-4·1·(-7200)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-180}{2*1}=\frac{-240}{2} =-120 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+180}{2*1}=\frac{120}{2} =60 $

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