x2+6x+8x=35

Solution for x2+6x+8x=35 equation:

x2+6x+8x=35

We move all terms to the left:

x2+6x+8x-(35)=0

We add all the numbers together, and all the variables

x^2+14x-35=0

a = 1; b = 14; c = -35;
Δ = b2-4ac
Δ = 142-4·1·(-35)
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-4\sqrt{21}}{2*1}=\frac{-14-4\sqrt{21}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+4\sqrt{21}}{2*1}=\frac{-14+4\sqrt{21}}{2}
$