x2+6x-12=0.7

Solution for x2+6x-12=0.7 equation:

x2+6x-12=0.7

We move all terms to the left:

x2+6x-12-(0.7)=0

We add all the numbers together, and all the variables

x^2+6x-12.7=0

a = 1; b = 6; c = -12.7;
Δ = b2-4ac
Δ = 62-4·1·(-12.7)
Δ = 86.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{86.8}}{2*1}=\frac{-6-\sqrt{86.8}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{86.8}}{2*1}=\frac{-6+\sqrt{86.8}}{2}
$