x2+6x-3.25=0

Solution for x2+6x-3.25=0 equation:

x2+6x-3.25=0

We add all the numbers together, and all the variables

x^2+6x-3.25=0

a = 1; b = 6; c = -3.25;
Δ = b2-4ac
Δ = 62-4·1·(-3.25)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-7}{2*1}=\frac{-13}{2}
=-6+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+7}{2*1}=\frac{1}{2}
=1/2
$