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x2+6x-352=0
We add all the numbers together, and all the variables
x^2+6x-352=0
a = 1; b = 6; c = -352;
Δ = b2-4ac
Δ = 62-4·1·(-352)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-38}{2*1}=\frac{-44}{2} =-22 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+38}{2*1}=\frac{32}{2} =16 $
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