x2+6x-832=0

Solution for x2+6x-832=0 equation:

x2+6x-832=0

We add all the numbers together, and all the variables

x^2+6x-832=0

a = 1; b = 6; c = -832;
Δ = b2-4ac
Δ = 62-4·1·(-832)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-58}{2*1}=\frac{-64}{2}
=-32
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+58}{2*1}=\frac{52}{2}
=26
$