If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x2+7=7x
We move all terms to the left:
x2+7-(7x)=0
We add all the numbers together, and all the variables
x^2-7x+7=0
a = 1; b = -7; c = +7;
Δ = b2-4ac
Δ = -72-4·1·7
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{21}}{2*1}=\frac{7-\sqrt{21}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{21}}{2*1}=\frac{7+\sqrt{21}}{2} $
| (3m-4)/4-1/5=m/4+3/10 | | (-2/3)x=14 | | (x−1)(x−2)(x−3)(x−4)(x−5)=0 | | (3v+2)=0 | | 2k-14=2k-13 | | (2y-3)(2y-1)=5y | | x^2+51=100 | | 4a=(20–4a)5 | | (14+x)/3=-4 | | 5-(6k+1)=(5k-3)-(k-2)*(5k-3)-(k-2) | | 5-6K-1=(5k-3)-(k-2)(5k-3)-(k-2) | | 0.25c-8=4 | | 3(m-5)=3(m+1) | | (3z-7)(8-z)=0 | | 5b-4=12b-8 | | 15^(y+6)=11 | | 6x+x=32 | | (2x+5)+(4x+6)=(2x+4x)+(5+6) | | 2x×4x=32 | | 5X+32=2X+3x42 | | (4t3+3t2)−(t3+t2+t)=(4t3+3t2)−(t3+t2+t)= | | 2x-5/10-1-x/5=0 | | 2x+15=-60 | | 160.3=10x-4= | | 92-x/159=175 | | (15/100)x=60 | | 5(2x-1)-4(3x+5)=2(6x-3)-7(2x-1) | | (6y)^2-24y=0 | | 15-(4+2x)=65 | | -7-6(1-6k)=-13-4k | | 3x+-10=2x+9 | | -5h(h+12)-(4h-2)=h-8 |