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x2+7x+5x-9=180
We move all terms to the left:
x2+7x+5x-9-(180)=0
We add all the numbers together, and all the variables
x^2+12x-189=0
a = 1; b = 12; c = -189;
Δ = b2-4ac
Δ = 122-4·1·(-189)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-30}{2*1}=\frac{-42}{2} =-21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+30}{2*1}=\frac{18}{2} =9 $
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