x2+80x+700=0

Solution for x2+80x+700=0 equation:

x2+80x+700=0

We add all the numbers together, and all the variables

x^2+80x+700=0

a = 1; b = 80; c = +700;
Δ = b2-4ac
Δ = 802-4·1·700
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-60}{2*1}=\frac{-140}{2}
=-70
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+60}{2*1}=\frac{-20}{2}
=-10
$