x2+8x-15=8x+1

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Solution for x2+8x-15=8x+1 equation:



x2+8x-15=8x+1
We move all terms to the left:
x2+8x-15-(8x+1)=0
We add all the numbers together, and all the variables
x^2+8x-(8x+1)-15=0
We get rid of parentheses
x^2+8x-8x-1-15=0
We add all the numbers together, and all the variables
x^2-16=0
a = 1; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·1·(-16)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*1}=\frac{-8}{2} =-4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*1}=\frac{8}{2} =4 $

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