x2+8x-4224=0

Solution for x2+8x-4224=0 equation:

x2+8x-4224=0

We add all the numbers together, and all the variables

x^2+8x-4224=0

a = 1; b = 8; c = -4224;
Δ = b2-4ac
Δ = 82-4·1·(-4224)
Δ = 16960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16960}=\sqrt{64*265}=\sqrt{64}*\sqrt{265}=8\sqrt{265}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{265}}{2*1}=\frac{-8-8\sqrt{265}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{265}}{2*1}=\frac{-8+8\sqrt{265}}{2}
$