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x2+8x-84=0
We add all the numbers together, and all the variables
x^2+8x-84=0
a = 1; b = 8; c = -84;
Δ = b2-4ac
Δ = 82-4·1·(-84)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-20}{2*1}=\frac{-28}{2} =-14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+20}{2*1}=\frac{12}{2} =6 $
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