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x2+8x-880=0
We add all the numbers together, and all the variables
x^2+8x-880=0
a = 1; b = 8; c = -880;
Δ = b2-4ac
Δ = 82-4·1·(-880)
Δ = 3584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3584}=\sqrt{256*14}=\sqrt{256}*\sqrt{14}=16\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-16\sqrt{14}}{2*1}=\frac{-8-16\sqrt{14}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+16\sqrt{14}}{2*1}=\frac{-8+16\sqrt{14}}{2} $
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