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x2+8x/7=0
We add all the numbers together, and all the variables
x^2+8x/7=0
We multiply all the terms by the denominator
x^2*7+8x=0
Wy multiply elements
7x^2+8x=0
a = 7; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·7·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*7}=\frac{-16}{14} =-1+1/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*7}=\frac{0}{14} =0 $
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