x2+8x=35

Solution for x2+8x=35 equation:

x2+8x=35

We move all terms to the left:

x2+8x-(35)=0

We add all the numbers together, and all the variables

x^2+8x-35=0

a = 1; b = 8; c = -35;
Δ = b2-4ac
Δ = 82-4·1·(-35)
Δ = 204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{204}=\sqrt{4*51}=\sqrt{4}*\sqrt{51}=2\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{51}}{2*1}=\frac{-8-2\sqrt{51}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{51}}{2*1}=\frac{-8+2\sqrt{51}}{2}
$