x2+9x-14=(x-7)(x+2)

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Solution for x2+9x-14=(x-7)(x+2) equation: 



x2+9x-14=(x-7)(x+2)

We move all terms to the left:

x2+9x-14-((x-7)(x+2))=0

We add all the numbers together, and all the variables

x^2+9x-((x-7)(x+2))-14=0

We multiply parentheses ..

x^2-((+x^2+2x-7x-14))+9x-14=0



We calculate terms in parentheses: -((+x^2+2x-7x-14)), so:

(+x^2+2x-7x-14)

We get rid of parentheses

x^2+2x-7x-14

We add all the numbers together, and all the variables

x^2-5x-14

Back to the equation:

-(x^2-5x-14)



We add all the numbers together, and all the variables

x^2+9x-(x^2-5x-14)-14=0

We get rid of parentheses

x^2-x^2+9x+5x+14-14=0

We add all the numbers together, and all the variables

14x=0

x=0/14

x=0

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